A planet has twice the radius but the mean density is $\frac{1}{4}^{th}$ as compared to earth. What is the ratio of escape velocity from earth to that from the planet
A planet has twice the radius but the mean density is $\frac{1}{4}^{th}$ as compared to earth. What is the ratio of escape velocity from earth to that from the planet
$3:1$
$1:2$
$1:1$
$2:1$
A planet has twice the radius but the mean density is $\frac{1}{4}^{th}$ as compared to earth. What is the ratio of escape velocity from earth to that from the planet
$v = R\sqrt {\frac{8}{3}\pi \rho G} $
$⇒ \frac{{{v_p}}}{{{v_e}}} = \frac{{{R_p}}}{{{R_e}}}\sqrt {\frac{{{\rho _p}}}{{{\rho _e}}}} =2\sqrt {\frac{1}{4}} = 1$
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