A person goes $10\, km$ north and $20\, km$ east. What will be displacement from initial point........$km$
$22.36$
$2$
$5$
$20$
A person goes $10\, km$ north and $20\, km$ east. What will be displacement from initial point........$km$
$\overrightarrow {AC} = \overrightarrow {AB} + \overrightarrow {BC} $
$AC = \sqrt {{{(AB)}^2} + {{(BC)}^2}} $
$ = \sqrt {{{(10)}^2} + {{(20)}^2}} $
$ = \sqrt {100 + 400} $$ = \sqrt {500} $$ = 22.36\,km$
$AC = \sqrt {{{(AB)}^2} + {{(BC)}^2}} $
$ = \sqrt {{{(10)}^2} + {{(20)}^2}} $
$ = \sqrt {100 + 400} $$ = \sqrt {500} $$ = 22.36\,km$