A particle when thrown, moves such that it passes from same height at $2$ and $10s$, the height is
$g$
$2g$
$5g$
$10g$
A particle when thrown, moves such that it passes from same height at $2$ and $10s$, the height is
If ${t_1}$ and ${t_2}$are the time, when body is at the same height then,
$h = \frac{1}{2}g\,{t_1}{t_2}$ $ = \frac{1}{2} \times g \times 2 \times 10 = 10\;g$