A particle starts from rest, accelerates at $2 \,ms^{-2}$ for $10\,s$ and then goes for constant speed for $30\,s$ and then decelerates at $ 4\, ms^{-2}$ till it stops. What is the distance travelled by it.........$m$
$750$
$800 $
$700 $
$850$
A particle starts from rest, accelerates at $2 \,ms^{-2}$ for $10\,s$ and then goes for constant speed for $30\,s$ and then decelerates at $ 4\, ms^{-2}$ till it stops. What is the distance travelled by it.........$m$
Velocity acquired by body in $10\,sec$
$v = 0 + 2 \times 10 = 20\,m/s$
and distance travelled by it in $10 \,sec$
${S_1} = \frac{1}{2} \times 2 \times {(10)^2} = 100\;m$
then it moves with constant velocity (20 \,m/s)for $30\;\sec $
$\;{S_2} = 20 \times 30 = 600\;m$
After that due to retardation $(4\,m/{s^2})$ it stops
${S_3} = \frac{{{v^2}}}{{2a}} = \frac{{{{(20)}^2}}}{{2 \times 4}} = 50\,m$
Total distance travelled ${S_1} + {S_2} + {S_3} = 750\,m$
$v = 0 + 2 \times 10 = 20\,m/s$
and distance travelled by it in $10 \,sec$
${S_1} = \frac{1}{2} \times 2 \times {(10)^2} = 100\;m$
then it moves with constant velocity (20 \,m/s)for $30\;\sec $
$\;{S_2} = 20 \times 30 = 600\;m$
After that due to retardation $(4\,m/{s^2})$ it stops
${S_3} = \frac{{{v^2}}}{{2a}} = \frac{{{{(20)}^2}}}{{2 \times 4}} = 50\,m$
Total distance travelled ${S_1} + {S_2} + {S_3} = 750\,m$
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