A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
Kinetic energy changes by $M{V^2}/4$
Momentum does not change
Momentum changes by $ 2MV$
Kinetic energy changes by $M{V^2}$
A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its
On the diametrically opposite points, the velocities have same magnitude but
opposite directions. Therefore change in momentum is
$\mathrm{Mv}-(-\mathrm{M} \mathrm{v})=2 \mathrm{Mv}$
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