A particle of mass m moving with horizontal speed $6\, m/sec$ as shown in figure. If $m < < M$ then for one dimensional elastic collision, the speed of lighter particle after collision will be
$2\,m/sec $ in original direction
$2 \,m/sec$ opposite to the original direction
$4\, m/sec$ opposite to the original direction
$4 \,m/sec$ in original direction
A particle of mass m moving with horizontal speed $6\, m/sec$ as shown in figure. If $m < < M$ then for one dimensional elastic collision, the speed of lighter particle after collision will be
${v_1} = \left( {\frac{{{m_1} - {m_2}}}{{{m_1} + {m_2}}}} \right)\,{u_1} + \frac{{2{m_2}{u_2}}}{{{m_1} + {m_2}}}$
Substituting $m1 = 0$ , ${v_1} = - {u_1} + 2{u_2}$
$⇒$ ${v_1} = - \,6 + 2(4)$ $ = 2m/s$
i.e. the lighter particle will move in original direction with the speed of $2\, m/s.$