A particle moves along $X-$axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6{t^2})\,m$. The initial velocity of the particle is.......$m/s$
A particle moves along $X-$axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6{t^2})\,m$. The initial velocity of the particle is.......$m/s$
$ - 5$
$6$
$ - 3$
$3$
A particle moves along $X-$axis in such a way that its coordinate $X$ varies with time $t$ according to the equation $x = (2 - 5t + 6{t^2})\,m$. The initial velocity of the particle is.......$m/s$
The velocity of the particle is
$\frac{{dx}}{{dt}} = \frac{d}{{dt}}(2 - 5t + 6{t^2}) = (0 - 5 + 12t)$
For initial velocity $t = 0$, hence $v = - 5\;m/s$.