A particle moves along $X-$axis as $x = 4(t - 2) + a{(t - 2)^2}$ Which of the following is true ?
The initial velocity of particle is $4$
The acceleration of particle is $2a$
The particle is at origin at $t = 0$
None of these
A particle moves along $X-$axis as $x = 4(t - 2) + a{(t - 2)^2}$ Which of the following is true ?
$x = 4(t - 2) + a{(t - 2)^2}$
At $t = 0,\,x = - 8 + 4a = 4a - 8$
$v = \frac{{dx}}{{dt}} = 4 + 2a(t - 2)$
At $t = 0,\;\;v = 4 - 4a = 4(1 - a)$
But acceleration,$a = \frac{{{d^2}x}}{{d{t^2}}} = 2a$
At $t = 0,\,x = - 8 + 4a = 4a - 8$
$v = \frac{{dx}}{{dt}} = 4 + 2a(t - 2)$
At $t = 0,\;\;v = 4 - 4a = 4(1 - a)$
But acceleration,$a = \frac{{{d^2}x}}{{d{t^2}}} = 2a$
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