A particle moves along a straight line such that its displacement at any time $t$ is given by $s = {t^3} - 6{t^2} + 3t + 4$ metres. The velocity when the acceleration is zero is........$m{s^{ - 1}}$
$3$
$ - 12$
$42$
$ - 9$
A particle moves along a straight line such that its displacement at any time $t$ is given by $s = {t^3} - 6{t^2} + 3t + 4$ metres. The velocity when the acceleration is zero is........$m{s^{ - 1}}$
$v = \frac{{ds}}{{dt}} = 3{t^2} - 12t + 3$ and $a = \frac{{dv}}{{dt}} = 6t - 12$
For $a = 0$, we have $t = 2$ and at $t = 2,\;v = - 9\;m{s^{ - 1}}$
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