A particle is moving in a circle with uniform speed $v$. In moving from a point to another diametrically opposite point
The momentum changes by $mv$
The momentum changes by $2mv$
The kinetic energy changes by $(1/2)mv^2$
The kinetic energy changes by $ mv^2$
A particle is moving in a circle with uniform speed $v$. In moving from a point to another diametrically opposite point
Momentum changes by $2\,mv$ but kinetic energy remains same.