A particle is kept at rest at the top of a sphere of diameter $42\, m$. When disturbed slightly, it slides down. At what height $‘h’ $ from the bottom, the particle will leave the sphere ........ $m$
A particle is kept at rest at the top of a sphere of diameter $42\, m$. When disturbed slightly, it slides down. At what height $‘h’ $ from the bottom, the particle will leave the sphere ........ $m$
$14$
$28 $
$35$
$7 $
A particle is kept at rest at the top of a sphere of diameter $42\, m$. When disturbed slightly, it slides down. At what height $‘h’ $ from the bottom, the particle will leave the sphere ........ $m$
As we know for hemisphere the particle will leave the sphere at height $h = 2r/3$
$h = \frac{2}{3} \times 21 = 14\,m$
but from the bottom $H = h + r = 14 + 21 = 35\,metre$
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