A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
$100$
$150 $
$200 $
$250 $
A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
$R = \frac{{{u^2}\sin 2\theta }}{g} = R \propto {u^2}.$ So if the speed of projection doubled, the range will becomes four times,
i.e., $4 \times 50 = 200\,m$