A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates about a fixed centre at an angular velocity ${\omega _0}$. If the length of the string and angular velocity are doubled, the tension in the string which was initially ${T_0}$ is now
${T_0}$
${T_0}/2$
$4{T_0}$
$8{T_0}$
A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates about a fixed centre at an angular velocity ${\omega _0}$. If the length of the string and angular velocity are doubled, the tension in the string which was initially ${T_0}$ is now
Tension in the string ${T_0} = mR\omega _0^2$
In the second case $T = m(2R)(4\omega _0^2) = 8mR\omega _0^2$$ = 8{T_0}$
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