A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as $40 \,kg$. If the lift is accelerated upwards with an acceleration of $2\,m/{s^2}$, then the weight recorded in the machine will be .......... $kg$ $(g = 10\,m/{s^2})$
$32$
$40$
$42$
$48$
A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as $40 \,kg$. If the lift is accelerated upwards with an acceleration of $2\,m/{s^2}$, then the weight recorded in the machine will be .......... $kg$ $(g = 10\,m/{s^2})$
In stationary lift man weighs $40\, kg$ i.e. $ 400 \,N.$
When lift accelerates upward it's apparent weight $ = m(g + a) = 40(10 + 2) = 480\;N$
$ i.e. $$48\, kg$ For the clarity of concepts in this problem kg-wt can be used in place of kg.
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