A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then
A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then
Lorry will come to rest in a shorter distance
Car will come to rest in a shorter distance
Both come to rest in a same distance
None of the above
A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then
${\rm{Stopping distance}} = \frac{{{\rm{kinetic energy}}}}{{{\rm{retarding force}}}}$==>$s = \frac{1}{2}\frac{{m{u^2}}}{F}$
If lorry and car both possess same kinetic energy and retarding force is also equal then both come to rest in the same distance.
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