A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers..........$m$
$3.6$
$28.8$
$36$
Cannot be calculated from the above graph
A lift is going up. The variation in the speed of the lift is as given in the graph. What is the height to which the lift takes the passengers..........$m$
Area of trapezium $ = \frac{1}{2} \times 3.6 \times (12 + 8) = 36.0\;m$
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