A cyclist turns around a curve at $15\, miles/hour$. If he turns at double the speed, the tendency to overturn is
Doubled
Quadrupled
Halved
Unchanged
A cyclist turns around a curve at $15\, miles/hour$. If he turns at double the speed, the tendency to overturn is
$F = \frac{{m{v^2}}}{r}$
$⇒$ $F \propto {v^2}$.
If $v$ becomes double then $F$ (tendency to overturn) will become four times.