A cyclist turns around a curve at 15 mile

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A cyclist turns around a curve at $15\, miles/hour$. If he turns at double the speed, the tendency to overturn is

A

Doubled

B

Quadrupled

C

Halved

D

Unchanged

A cyclist turns around a curve at $15\, miles/hour$. If he turns at double the speed, the tendency to overturn is

$F = \frac{{m{v^2}}}{r}$

$⇒$ $F \propto {v^2}$.

If $v$ becomes double then $F$ (tendency to overturn) will become four times.