A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be
A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be
$0.8 m/s^2$
$0.4 m/s^2$
$1.6\,{\pi ^2}\,m/{s^2}$
$0.4\,{\pi ^2}\,m/{s^2}$
A cycle wheel of radius 0.4 m completes one revolution in one second then the acceleration of a point on the cycle wheel will be
Centripetal acceleration $ = 4\pi^2n^2r=4\pi^2×(1)×0.4=1.6\pi^2$