A cord is used to lower vertically a block of mass $M$ by a distance $d$ with constant downward acceleration $\frac{g}{4}$. Work done by the cord on the block is
$Mg\frac{d}{4}$
$3Mg\frac{d}{4}$
$ - 3Mg\frac{d}{4}$
Mgd
A cord is used to lower vertically a block of mass $M$ by a distance $d$ with constant downward acceleration $\frac{g}{4}$. Work done by the cord on the block is
When the block moves vertically downward with acceleration $\frac{g}{4}$ then tension in the cord
$T = M\left( {g - \frac{g}{4}} \right)\; = \frac{3}{4}Mg$
Work done by the cord = $\overrightarrow F .\overrightarrow s = Fs\cos \theta $
= $Td\cos (180^\circ )$$ = - \left( {\frac{{3Mg}}{4}} \right) \times d$$ = - \frac{3}{4}Mgd$
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