A constant force acts on a body of mass $0.9 \,kg$ at rest for $10\,s$. If the body moves a distance of $250 \,m$, the magnitude of the force is.........$N$
$3$
$3.5$
$4.0$
$4.5$
A constant force acts on a body of mass $0.9 \,kg$ at rest for $10\,s$. If the body moves a distance of $250 \,m$, the magnitude of the force is.........$N$
$u = 0,S = 250\,m,\;t = 10\sec \;$
$S = ut + \frac{1}{2}a{t^2} $
$⇒$ $250 = \frac{1}{2}a{[10]^2} \Rightarrow a = 5m/{s^2}$
So, $F = ma = 0.9 \times 5 = 4.5N$
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