A car of mass $ ‘m’ $ is driven with acceleration $ ‘a’ $ along a straight level road against a constant external resistive force $ ‘R’.$ When the velocity of the car is $‘V’, $ the rate at which the engine of the car is doing work will be
A car of mass $ ‘m’ $ is driven with acceleration $ ‘a’ $ along a straight level road against a constant external resistive force $ ‘R’.$ When the velocity of the car is $‘V’, $ the rate at which the engine of the car is doing work will be
$RV$
$maV$
$(R + ma)V$
$(ma - R)V$
A car of mass $ ‘m’ $ is driven with acceleration $ ‘a’ $ along a straight level road against a constant external resistive force $ ‘R’.$ When the velocity of the car is $‘V’, $ the rate at which the engine of the car is doing work will be
Force required to move with constant velocity
Power $ = FV $
Force is required to oppose the resistive force $R$ and also to accelerate the body of mass with acceleration a.
Power = $(R + ma)V$
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