A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is
A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is
$25 \times {10^3}m$
$12.5 \times {10^3}m$
$50 \times {10^2}m$
$25 \times {10^2}m$
A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is
$R = \frac{{{u^2}\sin 2\theta }}{g} = \frac{{{{(500)}^2} \times \sin 30^\circ }}{{10}} = 12.5 \times {10^3}\,m$