A bomber plane moves horizontally with a speed of $500\, m/s$ and a bomb released from it, strikes the ground in $10\, sec$. Angle at which it strikes the ground will be $(g = 10\,\,m/{s^2})$
A bomber plane moves horizontally with a speed of $500\, m/s$ and a bomb released from it, strikes the ground in $10\, sec$. Angle at which it strikes the ground will be $(g = 10\,\,m/{s^2})$
${\tan ^{ - 1}}\left( {\frac{1}{5}} \right)$
$\tan \,\left( {\frac{1}{5}} \right)$
${\tan ^{ - 1}}(1)$
${\tan ^{ - 1}}(5)$
A bomber plane moves horizontally with a speed of $500\, m/s$ and a bomb released from it, strikes the ground in $10\, sec$. Angle at which it strikes the ground will be $(g = 10\,\,m/{s^2})$
Horizontal component of velocity $v_x= 500\, m/s$
and vertical components of velocity while striking the ground.
${v_y} = 0 + 10 \times 10 = 100\,m/s$
Angle with which it strikes the ground.
$\theta = {\tan ^{ - 1}}\left( {\frac{{{v_y}}}{{{v_x}}}} \right) = {\tan ^{ - 1}}\left( {\frac{{100}}{{500}}} \right) = {\tan ^{ - 1}}\left( {\frac{1}{5}} \right)$
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