A bomb of $12 \,kg$ explodes into two pieces of masses $4 \,kg $ and $8 \,kg$. The velocity of $8\,kg$ mass is $6 m/sec$. The kinetic energy of the other mass is ............. $\mathrm{J}$
A bomb of $12 \,kg$ explodes into two pieces of masses $4 \,kg $ and $8 \,kg$. The velocity of $8\,kg$ mass is $6 m/sec$. The kinetic energy of the other mass is ............. $\mathrm{J}$
$48 $
$32$
$24$
$288$
A bomb of $12 \,kg$ explodes into two pieces of masses $4 \,kg $ and $8 \,kg$. The velocity of $8\,kg$ mass is $6 m/sec$. The kinetic energy of the other mass is ............. $\mathrm{J}$
As the initial momentum of bomb was zero, therefore after explosion two parts should possess numerically equal momentum
i.e. ${m_A}{v_A} = {m_B}{v_B}$
==> $4 \times {v_A} = 8 \times 6$
==> ${v_A} = 12\;m/s$
Kinetic energy of other mass $A$ , = $\frac{1}{2}{m_A}v_A^2$ = $\frac{1}{2} \times 4 \times {(12)^2}= 288 J.$
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