A body weight $ W $ newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
A body weight $ W $ newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
$\frac{W}{2}$
$\frac{{2W}}{3}$
$\frac{{4W}}{9}$
$\frac{{8W}}{{27}}$
A body weight $ W $ newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
$g' = g\,{\left( {\frac{R}{{R + h}}} \right)^2} = \frac{4}{9}g$
$\therefore \,\,W' = \frac{4}{9}W$
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