A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in $6$ seconds. The ratio of the distances travelled by the body in the first second and the seventh second is
A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in $6$ seconds. The ratio of the distances travelled by the body in the first second and the seventh second is
$1:1$
$11:1$
$1:2$
$1:11$
A body thrown vertically upwards with an initial velocity $u$ reaches maximum height in $6$ seconds. The ratio of the distances travelled by the body in the first second and the seventh second is
Time of ascent $ = \frac{u}{g} = 6\;\sec \Rightarrow u = 60\;m/s$
Distance in first second ${h_{{\rm{first}}}} = 60 - \frac{g}{2}(2 \times 1 - 1) = 55\;m$
Distance in seventh second will be equal to the distance in first second of vertical downward motion ${h_{{\rm{seventh}}}} = \frac{g}{2}(2 \times 1 - 1) = 5\;m$
$⇒$ ${h_{{\rm{first}}}}/{h_{{\rm{seventh}}}}$$ = 11:1$
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