A body of weight $2\, kg$ is suspended as shown in the figure. The tension ${T_1}$ in the horizontal string (in kg wt) is
$2/\sqrt 3 $
$\sqrt 3 /2$
$2\sqrt 3 $
$2$
A body of weight $2\, kg$ is suspended as shown in the figure. The tension ${T_1}$ in the horizontal string (in kg wt) is
$T\sin 30 = 2kg\,wt$
$⇒$ $T = 4\,kg\,wt$
${T_1} = T\cos 30^o$
$ = 4\cos 30^o$
$ = 2\sqrt 3 $
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