A body of mass m rises to height $h = R/5$ from the earth's surface, where $R$ is earth's radius. If $g$ is acceleration due to gravity at earth's surface, the increase in potential energy is
A body of mass m rises to height $h = R/5$ from the earth's surface, where $R$ is earth's radius. If $g$ is acceleration due to gravity at earth's surface, the increase in potential energy is
$mgh$
$\frac{4}{5}mgh$
$\frac{5}{6}mgh$
$\frac{6}{7}mgh$
A body of mass m rises to height $h = R/5$ from the earth's surface, where $R$ is earth's radius. If $g$ is acceleration due to gravity at earth's surface, the increase in potential energy is
$\Delta U = \frac{{mgh}}{{1 + h/R}}$
Substituting $R = 5h$ we get $\Delta U = \frac{{mgh}}{{1 + 1/5}} = \frac{5}{6}mgh$
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