A body of mass $m$ hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of ${60^°}$ with the vertical. The tension in the string at mean position is
A body of mass $m$ hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of ${60^°}$ with the vertical. The tension in the string at mean position is
$2\,mg$
$mg$
$3\,mg$
$\sqrt 3\, mg$
A body of mass $m$ hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of ${60^°}$ with the vertical. The tension in the string at mean position is
When body is released from the position p (inclined at angle $\theta$ from vertical) then velocity at mean position
$v = \sqrt {2gl(1 - \cos \theta )} $
Tension at the lowest point = $mg + \frac{{m{v^2}}}{l}$
$ = mg + \frac{m}{l}[2gl(1 - \cos 60)]$$ = mg + mg = 2\,mg$
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