A body of mass $5\,kg$ rests on a rough horizontal surface of coefficient of friction $0.2.$ The body is pulled through a distance of $10\,m$ by a horizontal force of $25\, N$. The kinetic energy acquired by it is ......... $J$
A body of mass $5\,kg$ rests on a rough horizontal surface of coefficient of friction $0.2.$ The body is pulled through a distance of $10\,m$ by a horizontal force of $25\, N$. The kinetic energy acquired by it is ......... $J$
$330$
$150$
$100$
$50$
A body of mass $5\,kg$ rests on a rough horizontal surface of coefficient of friction $0.2.$ The body is pulled through a distance of $10\,m$ by a horizontal force of $25\, N$. The kinetic energy acquired by it is ......... $J$
Kinetic energy acquired by body = (Total work done on the body) -(work against friction)
$ = F \times S - \mu mgS = 25 \times 10 - 0.2 \times 5 \times 10 \times 10$
$ = 250 - 100 = 150\;Joule$
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