A body of mass 4 kg moving with velocity

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A body of mass $4\, kg$ moving with velocity $12 \,m/s$ collides with another body of mass $6\, kg$ at rest. If two bodies stick together after collision, then the loss of kinetic energy of system is .............. $J$

A

$0$

B

$288$

C

$172.8 $

D

$144$

A body of mass $4\, kg$ moving with velocity $12 \,m/s$ collides with another body of mass $6\, kg$ at rest. If two bodies stick together after collision, then the loss of kinetic energy of system is .............. $J$

Loss in K.E. = $\frac{{{m_1}{m_2}}}{{2({m_1} + {m_2})}}{\left( {{u_1} - {u_2}} \right)^2}$
= $\frac{{4 \times 6}}{{2 \times 10}} \times {(12 - 0)^2}$

$= 172.8 \,J$