A body of $2\, kg$ has an initial speed $5ms^{-1}$. A force acts on it for some time in the direction of motion. The force time graph is shown in figure. The final speed of the body. .......... $m{s^{ - 1}}$
$9.25$
$5$
$14.25$
$4.25$
A body of $2\, kg$ has an initial speed $5ms^{-1}$. A force acts on it for some time in the direction of motion. The force time graph is shown in figure. The final speed of the body. .......... $m{s^{ - 1}}$
Impulse = Change in momentum $ = m({v_2} - {v_1})$…(i)
Again impulse = Area between the graph and time axis $ = \frac{1}{2} \times 2 \times 4 + 2 \times 4 + \frac{1}{2}(4 + 2.5) \times 0.5 + 2 \times 2.5$
$ = 4 + 8 + 1.625 + 5$ $ = 18.625$...(ii)
From (i) and (ii), $m({v_2} - {v_1}) = 18.625$
$⇒$ ${v_2} = \frac{{18.625}}{m} + {v_1} = \frac{{18.625}}{2} + 5 = 14.25\;m/s$
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