A body $A$ starts from rest with an acceleration ${a_1}$. After $2$ seconds, another body $B$ starts from rest with an acceleration ${a_2}$. If they travel equal distances in the $5$th second, after the start of $A$, then the ratio ${a_1}:{a_2}$ is equal to
$5:9$
$5:7$
$9:5$
$9:7$
A body $A$ starts from rest with an acceleration ${a_1}$. After $2$ seconds, another body $B$ starts from rest with an acceleration ${a_2}$. If they travel equal distances in the $5$th second, after the start of $A$, then the ratio ${a_1}:{a_2}$ is equal to
According to problem
Distance travelled by body $A$ in ${5^{th}}$sec and distance travelled by body $B$ in ${3^{rd}}$ sec. of its motion are equal.
$0 + \frac{{{a_1}}}{2}(2 \times 5 - 1) = 0 + \frac{{{a_2}}}{2}[2 \times 3 - 1]$
$9{a_1} = 5{a_2} \Rightarrow \frac{{{a_1}}}{{{a_2}}} = \frac{5}{9}$
Distance travelled by body $A$ in ${5^{th}}$sec and distance travelled by body $B$ in ${3^{rd}}$ sec. of its motion are equal.
$0 + \frac{{{a_1}}}{2}(2 \times 5 - 1) = 0 + \frac{{{a_2}}}{2}[2 \times 3 - 1]$
$9{a_1} = 5{a_2} \Rightarrow \frac{{{a_1}}}{{{a_2}}} = \frac{5}{9}$
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