A block rests on a rough inclined plane making an angle of ${30^o}$ with the horizontal. The coefficient of static friction between the block and the plane is $0.8$. If the frictional force on the block is $10 \,N$, the mass of the block (in kg) is (take $g = 10\,\,m/{s^2})$
A block rests on a rough inclined plane making an angle of ${30^o}$ with the horizontal. The coefficient of static friction between the block and the plane is $0.8$. If the frictional force on the block is $10 \,N$, the mass of the block (in kg) is (take $g = 10\,\,m/{s^2})$
$2$
$4$
$1.6$
$2.5$
A block rests on a rough inclined plane making an angle of ${30^o}$ with the horizontal. The coefficient of static friction between the block and the plane is $0.8$. If the frictional force on the block is $10 \,N$, the mass of the block (in kg) is (take $g = 10\,\,m/{s^2})$
Angle of repose $\alpha = {\tan ^{ - 1}}(\mu ) = {\tan ^{ - 1}}(0.8) = 38.6^\circ $
Angle of inclined plane is given $\theta = 30^\circ $.
It means block is at rest therefore,
Static friction $=$ component of weight in downward direction $ = mg\sin \theta = 10\;N$
$\therefore m = \frac{{10}}{{9 \times \sin 30^\circ }} = 2\;kg$
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