A block of mass m initially at rest is dropped from a height $h$ on to a spring of force constant $k$. the maximum compression in the spring is $x$ then
$mgh = \frac{1}{2}k{x^2}$
$mg(h + x) = \frac{1}{2}k{x^2}$
$mgh = \frac{1}{2}k{(x + h)^2}$
$mg(h + x) = \frac{1}{2}k{(x + h)^2}$
A block of mass m initially at rest is dropped from a height $h$ on to a spring of force constant $k$. the maximum compression in the spring is $x$ then
Change in gravitational potential energy
$=$ Elastic potential energy stored in compressed spring
$ \Rightarrow mg(h + x) = \frac{1}{2}k{x^2}$
$=$ Elastic potential energy stored in compressed spring
$ \Rightarrow mg(h + x) = \frac{1}{2}k{x^2}$