A block of mass $5\,kg$ is moving horizontally at a speed of $1.5\, m/s$. A perpendicular force of $5\,N$ acts on it for $4 \,sec$. What will be the distance of the block from the point where the force started acting ........... $m$
A block of mass $5\,kg$ is moving horizontally at a speed of $1.5\, m/s$. A perpendicular force of $5\,N$ acts on it for $4 \,sec$. What will be the distance of the block from the point where the force started acting ........... $m$
$10 $
$8$
$6$
$2$
A block of mass $5\,kg$ is moving horizontally at a speed of $1.5\, m/s$. A perpendicular force of $5\,N$ acts on it for $4 \,sec$. What will be the distance of the block from the point where the force started acting ........... $m$
${S_{{\rm{Horizontal}}}} = ut = 1.5 \times 4 = 6\,m$
${S_{{\rm{Vertical}}}} = \frac{1}{2}a{t^2} = \frac{1}{2}\frac{F}{m}{t^2} = \frac{1}{2} \times 1 \times 16 = 8\,m$
${S_{{\rm{Net}}}} = \sqrt {{6^2} + {8^2}} = 10\,m$
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