A block is kept on a frictionless inclined surface with angle of inclination '$\alpha$'. The incline is given an acceleration $ 'a'$ to keep the block stationary. Then a is equal to
A block is kept on a frictionless inclined surface with angle of inclination '$\alpha$'. The incline is given an acceleration $ 'a'$ to keep the block stationary. Then a is equal to
$g$
$g \tan \alpha$
$g / \tan\alpha$
$g \,cosec \alpha $
A block is kept on a frictionless inclined surface with angle of inclination '$\alpha$'. The incline is given an acceleration $ 'a'$ to keep the block stationary. Then a is equal to
Let the mass of a block is m. It will remains stationary if forces acting on it are in equilibrium
i.e, $ma\cos \alpha = mg\sin \alpha $
$⇒$ $a = g\tan \alpha $
Here $ma$ = Pseudo force on block, $mg = Weight.$
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