A balloon starts rising from the ground with an acceleration of $1.25\, m/s^2$ after $8\,s$, a stone is released from the balloon. The stone will ($g = 10 \,m/s^2$)
A balloon starts rising from the ground with an acceleration of $1.25\, m/s^2$ after $8\,s$, a stone is released from the balloon. The stone will ($g = 10 \,m/s^2$)
Reach the ground in $4$ second
Begin to move down after being released
Have a displacement of $50 m$
Cover a distance of $40 m$ in reaching the ground
A balloon starts rising from the ground with an acceleration of $1.25\, m/s^2$ after $8\,s$, a stone is released from the balloon. The stone will ($g = 10 \,m/s^2$)
$v =1.25 \times 8 m / s =10\; m / s$
$s =\frac{1}{2} \times 1.25 \times 8 \times 8\; m / s =40 m$
now, $40=-10 t +\frac{1}{2} \times 10 \times t ^2$
$5 t^2-10 t-40=0$
$t^2-2 t-8=0$
hence, $t=4 s$
$s=40 \;m$.
displacement $=40\; m$
Just after being released the stone has an upward velocity, so it will move upwards first.
distance in an upward direction before stopping $d$.
$d =\frac{ v ^2- u ^2}{2 g }=\frac{10^2-0^2}{2 * 10}=5\; m$
and distance $= s +2 d =50 m$
So the distance covered is $50\; m$ and the displacement is $40\; m$.
Other Language