A ball $P$ is dropped vertically and another ball Q is thrown horizontally with the same velocities from the same height and at the same time. If air resistance is neglected, then
A ball $P$ is dropped vertically and another ball Q is thrown horizontally with the same velocities from the same height and at the same time. If air resistance is neglected, then
Ball P reaches the ground first
Ball Q reaches the ground first
Both reach the ground at the same time
The respective masses of the two balls will decide the time
A ball $P$ is dropped vertically and another ball Q is thrown horizontally with the same velocities from the same height and at the same time. If air resistance is neglected, then
Vertical component of velocities of both the balls are same and equal to zero. So $t = \sqrt {\frac{{2h}}{g}} $
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