A ball of mass ${m_1}$ and another ball of mass ${m_2}$ are dropped from equal height. If time taken by the balls are ${t_1}$ and ${t_2}$ respectively, then
A ball of mass ${m_1}$ and another ball of mass ${m_2}$ are dropped from equal height. If time taken by the balls are ${t_1}$ and ${t_2}$ respectively, then
${t_1} = \frac{{{t_2}}}{2}$
${t_1} = {t_2}$
${t_1} = 4{t_2}$
${t_1} = \frac{{{t_2}}}{4}$
A ball of mass ${m_1}$ and another ball of mass ${m_2}$ are dropped from equal height. If time taken by the balls are ${t_1}$ and ${t_2}$ respectively, then
The time of fall is independent of the mass.
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