A ball is thrown vertically up ward. It has a speed of $10\;m/sec$ when it has reached one half of its maximum height. How high ($m$ માં) does the ball rise? (Take $g = 10 \;m/s^2$)
A ball is thrown vertically up ward. It has a speed of $10\;m/sec$ when it has reached one half of its maximum height. How high ($m$ માં) does the ball rise? (Take $g = 10 \;m/s^2$)
$5$
$10$
$15$
$20$
A ball is thrown vertically up ward. It has a speed of $10\;m/sec$ when it has reached one half of its maximum height. How high ($m$ માં) does the ball rise? (Take $g = 10 \;m/s^2$)
Let particle thrown with velocity $u$ and its maximum height is $H$ then $H = \frac{{{u^2}}}{{2g}}$
When particle is at a height $H/2$, then its speed is $10\, m/s$
From equation ${v^2} = {u^2} - 2gh$
${(10)^2} = {u^2} - 2g\left( {\frac{H}{2}} \right) = {u^2} - 2g\frac{{{u^2}}}{{4g}}$$ \Rightarrow {u^2} = 200$
Maximum height $ \Rightarrow H = \frac{{{u^2}}}{{2g}} = \frac{{200}}{{2 \times 10}} = 10\;m$
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