A ball is projected with kinetic energy $E$ at an angle of ${45^o}$ to the horizontal. At the highest point during its flight, its kinetic energy will be
A ball is projected with kinetic energy $E$ at an angle of ${45^o}$ to the horizontal. At the highest point during its flight, its kinetic energy will be
Zero
$\frac{E}{2}$
$\frac{E}{{\sqrt 2 }}$
$E$
A ball is projected with kinetic energy $E$ at an angle of ${45^o}$ to the horizontal. At the highest point during its flight, its kinetic energy will be
$E' = E{\cos ^2}\theta = E{\cos ^2}(45^\circ ) = \frac{E}{2}$
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