$\overrightarrow A = 2\hat i + \hat j,\,B = 3\hat j - \hat k$ and $\overrightarrow C = 6\hat i - 2\hat k$.Value of $\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C $ would be
$20\hat i + 5\hat j + 4\hat k$
$20\hat i - 5\hat j - 4\hat k$
$4\hat i + 5\hat j + 20\hat k$
$5\hat i + 4\hat j + 10\hat k$
$\overrightarrow A = 2\hat i + \hat j,\,B = 3\hat j - \hat k$ and $\overrightarrow C = 6\hat i - 2\hat k$.Value of $\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C $ would be
$\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C = (2\hat i + \hat j) - 2(3\hat j - \hat k) + 3(6\hat i - 2\hat k)$
$ = 2\hat i + \hat j - 6\hat j + 2\hat k + 18\hat i - 6\hat k$
=$20\hat i - 5\hat j - 4\hat k$
$ = 2\hat i + \hat j - 6\hat j + 2\hat k + 18\hat i - 6\hat k$
=$20\hat i - 5\hat j - 4\hat k$
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